Home Chemistry Solution & Colligative Properties General What weight of the non-volatile solute urea …
Chemistry Solution & Colligative Properties General Numeric Response
Published on: August 13, 2026

What weight of the non-volatile solute urea (NH2—CO—NH2) needs to be dissolved in 100g of water, in order to decrease the vapour-pressure of water by 25% ? What will be the molality of the solution ?

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
75

Let the vapour-pressure of water = 100

∴ Vapour-pressure of urea solution = 75

By Raoult’s law

= .....(1)

In equation(1) w (wt. of urea) = ?

m(mol. wt. of urea) = 60

W(wt. of water) = 100 g

M(mol. wt. of water) = 18 g

P0(V.P of water) = 100

Ps(V.P. of solution) = 75

So, =

On solving we get, w = 111.1 g

Molality of urea solution

=

= = 18.5 M

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.